SCIScience

Projectile Motion

Calculate projectile range, maximum height, and flight time from initial velocity and launch angle. Assumes flat ground and no air resistance.

m/s
°

Try an example

How It Works

Formula

R=v2sin(2θ)gR = \frac{v^2 \sin(2\theta)}{g}

H=v2sin2(θ)2gH = \frac{v^2 \sin^2(\theta)}{2g}

T=2vsin(θ)gT = \frac{2 v \sin(\theta)}{g}

tpeak=vsin(θ)gt_{peak} = \frac{v \sin(\theta)}{g}

Where

RR

Horizontal range(m)

HH

Maximum height(m)

TT

Total flight time(s)

tpeakt_{peak}

Time to reach peak(s)

vv

Initial velocity(m/s)

θ\theta

Launch angle from horizontal(°)

gg

Gravitational acceleration (9.81)(m/s²)

Enter the initial velocity in m/s and the launch angle in degrees. The calculator computes the horizontal range, maximum height, total flight time, and time to reach peak height using standard projectile motion equations with g = 9.81 m/s².

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