विश्वास अंतराल कैलकुलेटर

$\bar{x} \pm t^* \cdot \frac{s}{\sqrt{n}}, \qquad df = n - 1$

$\hat{p} = \frac{x}{n}$

$\mathrm{CI}_{\mathrm{Wilson}} = \frac{\hat{p} + \frac{z^{*2}}{2n} \pm z^*\sqrt{\frac{\hat{p}(1-\hat{p})}{n} + \frac{z^{*2}}{4n^2}}}{1 + \frac{z^{*2}}{n}}$

$SE_{\bar{x}} = \frac{s}{\sqrt{n}}, \qquad SE_{\hat{p}} = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$